• 4

A PHP Error was encountered

Severity: Notice

Message: Undefined index: userid

Filename: views/question.php

Line Number: 191


File: /home/prodcxja/public_html/questions/application/views/question.php
Line: 191
Function: _error_handler

File: /home/prodcxja/public_html/questions/application/controllers/Questions.php
Line: 433
Function: view

File: /home/prodcxja/public_html/questions/index.php
Line: 315
Function: require_once

name Punditsdkoslkdosdkoskdo

PHP Warning: Invalid argument supplied for foreach()

Why am I getting this PHP Warning?

Invalid argument supplied for foreach()

Here is my code:

// look for text file for this keyword
if (empty($site["textdirectory"])) {
    $site["textdirectory"] = "text";
if (file_exists(ROOT_DIR.$site["textdirectory"].'/'.urlencode($q).'.txt')) {
    $keywordtext = 
else {
    $keywordtext = null;

$keywordsXML = getEbayKeywords($q);

foreach($keywordsXML->PopularSearchResult as $item) {
    $topicsString = $item->AlternativeSearches;
   $relatedString = $item->RelatedSearches;
   if (!empty($topicsString)) {
        $topics =  split(";",$topicsString);
    if (!empty($relatedString)) {
        $related = split(";",$relatedString);


$node = array();
$node['keywords'] = $q;


$xml = ebay_rss($node);

$ebayItems = array();
$totalItems = count($xml->channel->item);

$totalPages = $totalItems / $pageSize;

$i = 0;
foreach  ($xml->channel->item as $item) {
  $ebayRss = 

    if ($i>=($pageSize*($page-1)) && $i<($pageSize*$page)) {
        $newItem = array();
        $newItem['title'] = $item->title;
        $newItem['link'] = buyLink($item->link, $q);
        $newItem['image'] = ebay_stripImage($item->description);
        $newItem['currentbid'] = ebay_convertPrice($item->description);
        $newItem['bidcount'] = $ebayRss->BidCount;
        $newItem['endtime'] = ebay_convertTime($ebayRss->ListingEndTime);
        $newItem['type'] = $ebayRss->ListingType;
        if (!empty($ebayRss->BuyItNowPrice)) {
            $newItem['bin'] = ebay_convertPrice($item->description);
        array_push($ebayItems, $newItem);

$pageNumbers = array();
for ($i=1; $i<=$totalPages; $i++) {
    array_push($pageNumbers, $i);


// get user guides
$guidesXML = getEbayGuides($q);
$guides = array();
foreach ($guidesXML->guide as $guideXML) {
    $guide = array();
    $guide['url'] = makeguideLink($guideXML->url, $q);
    $guide['title'] = $guideXML->title;
    $guide['desc'] = $guideXML->desc;

What causes this warning?

    • Check out the {} button on the edit screen: It'll format the code for you like i've done now ;)
      • 1
    • Because you supplied an invalid argument to foreach. Did you check what you feed into it? var_dump can help you.
      • 2
    • It has a PHP Warning: Invalid argument supplied for all three: foreach($keywordsXML->PopularSearchResult as $item) { foreach ($xml->channel->item as $item) { foreach ($guidesXML->guide as $guideXML) {

You should check that what you are passing to foreach is an array by using the is_array function

If you are not sure it's going to be an array you can always check using the following PHP example code:

if (is_array($variable)) {

  foreach ($variable as $item) {
   //do something
  • 89
Reply Report
      • 1
    • Excellent. I was having an issue for a custom Wordpress plugin where I parse an RSS feed. This feed doesn't always have content by default, and expires until there is more content. So the array is not always populated. This solved the "offset" warnings I was getting in that case.
    • Why, I'm asking what would be causing me to get. Why am I getting a PHP Warning: Invalid argument supplied for foreach() on three of my foreach in my script.

This means that you are doing a foreach on something that is not an array.

Check out all your foreach statements, and look if the thing before the as, to make sure it is actually an array. Use var_dump to dump it.

Then fix the one where it isn't an array.

How to reproduce this error:

$skipper = "abcd";
foreach ($skipper as $item){       //the warning happens on this line.
    print "ok";

Make sure $skipper is an array.

  • 12
Reply Report

Because, on whatever line the error is occurring at (you didn't tell us which that is), you're passing something to foreach that is not an array.

Look at what you're passing into foreach, determine what it is (with var_export), find out why it's not an array... and fix it.

Basic, basic debugging.

  • 7
Reply Report

Warm tip !!!

This article is reproduced from Stack Exchange / Stack Overflow, please click

Trending Tags

Related Questions