3Answers
  • 9
name

A PHP Error was encountered

Severity: Notice

Message: Undefined index: userid

Filename: views/question.php

Line Number: 191

Backtrace:

File: /home/prodcxja/public_html/questions/application/views/question.php
Line: 191
Function: _error_handler

File: /home/prodcxja/public_html/questions/application/controllers/Questions.php
Line: 433
Function: view

File: /home/prodcxja/public_html/questions/index.php
Line: 315
Function: require_once

name Punditsdkoslkdosdkoskdo

Dynamic Resource Loading Android

I'm trying to find a way to open resources whose name is determined at runtime only.

More specifically, I want to have a XML that references a bunch of other XML files in the application apk. For the purpose of explaining, let's say the main XML is main.xml and the other XML are file1.xml, file2.xml and fileX.xml. What I want is to read main.xml, extract the name of the XML I want (fileX.xml), for example, and then read fileX.xml. The problem I face is that what I extract form main.xml is a string and I can't find a way to change that to R.raw.nameOfTheFile.

Anybody has an idea?

I don't want to:

  • regroup everything in one huge XML file
  • hardcode main.xml in a huge switch case that links a number/string to the resource ID
    • i faced a similar problem but I am not getting any accepted answer for this. Can anybody start bounty for this question?

I haven't used it with raw files or xml layout files, but for drawables I use this:

getResources().getIdentifier("fileX", "drawable","com.yourapppackage.www");

to get the identifier (R.id) of the resource. You would need to replace drawable with something else, maybe raw or layout (untested).

  • 58
Reply Report

I wrote this handy little helper method to encapsulate this:

public static String getResourceString(String name, Context context) {
    int nameResourceID = context.getResources().getIdentifier(name, "string", context.getApplicationInfo().packageName);
    if (nameResourceID == 0) {
        throw new IllegalArgumentException("No resource string found with name " + name);
    } else {
        return context.getString(nameResourceID);
    }
}
  • 24
Reply Report